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00:00 - 00:59 | the question is differentiate the following functions with respect to X tan inverse square root 1 + cos x upon 1 minus Cos 60 less than 5 so first of all I didn't consider this function as y y is equals to 10 inverse 1 + cos x upon 1 minus cos x and we have to find DY by DX to DY by DX equals to DY DX of tan inverse square root 1 + cos x upon 1 minus cos x |

01:00 - 01:59 | first we will simplify this term now we know that cos 2x equals to 2 cos square x - 1 and 2 equals to 1 minus 2 sin square x will use this to identify and we get DY DX tan inverse 1 + 2 cos square x by 2 minus 1 upon 1 minus 1 minus 2 sin square x into this implies DY DX tan inverse |

02:00 - 02:59 | 1 + 2 cos square x by 2 minus 1 upon 1 minus 1 + 2 sin square x by 2 this implies DY DX tan inverse 1 and 1 will be cancel out and here also one and one will be considered so we get 2 cos square x by 2 upon 2 sin square x by 2 square root 2 and 2 will be cancelled out and we get DB |

03:00 - 03:59 | x of tan inverse cos square x minus 2 upon sin square x by 2 equals to cos square x by 2 and at what is square x by 2 now this implies DY DX of tan inverse X by 2 and we can write cortex B to as tan pi by 2 minus 2 this implies DY by DX equals to 1 by DX pi by 2 minus x by 2 equal to pi by 2 is 0 and 1 - x b |

04:00 - 04:59 | is minus one by X equals to minus 1 by 2 and we are done |