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Let the dimensions of a rectangular prism is L * W * H.
Then, the surface area is:
SA(1)= 2WL + 2WH + 2LH= 2 ( WL+WH+LH)
Now we need to determine the surface area if the dimensions doubles.
Then, the dimensions now are: 2L *2W * 2H
==> SA(2)= 2( 4WL + 4WH + 4LH)
==> SA(2)= 8 (WL+ WH + LH)
==> SA(2)= 4* SA(1)
Then, we notice that if the dimensions doubles, the surface area is 4 times the original surface area.
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