On planet X a rock thrown from a height of 25 m, in the horizontal direction with a velocity 12 m/s strikes the ground after traveling 32 m. What is the gravitational acceleration on X.

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A rock is thrown with a velocity of 12 m/s in the horizontal direction at a height of 25 m. It travels 32 m before it strikes the ground.

Let the gravitational acceleration on planet X be x m/s^2. The time taken by the rock to travel the 25 m...

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A rock is thrown with a velocity of 12 m/s in the horizontal direction at a height of 25 m. It travels 32 m before it strikes the ground.

Let the gravitational acceleration on planet X be x m/s^2. The time taken by the rock to travel the 25 m before it strikes the ground can be determined by using the relation s = u*t + (1/2)*a*t^2. Substituting the values in the problem 25 = 0*t + (1/2)*x*t^2.

The horizontal distance traveled by the rock in time t is given by 12*t = 32.

25 = (x*t^2)/2 gives t = sqrt(50/x)

Substituting this in 12*t = 32 gives 12*sqrt(50/x) = 32

=> sqrt(50/x) = 32/12

=> 50/x = 64/9

=> x = 50*9/64 = 7.03125 m/s^2

The gravitational acceleration on planet X is 7.03125 m/s^2.

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