# What is the frequency of the light emitted by atomic Hydrogen according to Balmer's formula with n = 2 and m = 6? Is 7.31*10^14 Hz, the correct value for the frequency? Balmer's formula gives the wavelength of light emitted by the hydrogen atom. If the wavelength is represented by L, the formula gives L = K*m^2/(m^2 - n^2) where m and n are integers and K is a constant. The constant K = 3645.6*10^-7 for n = 2.

If n =...

Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Balmer's formula gives the wavelength of light emitted by the hydrogen atom. If the wavelength is represented by L, the formula gives L = K*m^2/(m^2 - n^2) where m and n are integers and K is a constant. The constant K = 3645.6*10^-7 for n = 2.

If n = 2 and m = 6, the wavelength L = 4.1013*10^-7 m.

The frequency (f) and wavelength (L) of a wave are related f*L = c, where c is the speed of light or 299792458 m/s. by for K.

This gives the frequency of the wave with wavelength 4.1013*10^-7, f = 299792458/(4.1013*10^-7) = 7.31*10^14 Hz.

You have arrived at the correct value of the frequency of light for the given values of m and n.

Approved by eNotes Editorial Team