What is the force required? If the coefficient of friction between a block of wood that weighs 6 kg and the surface it is placed on is .6, what is the horizontal force that is being applied if the block is moving at a constant velocity of 5 m/s.

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The force of kinetic friction is given by the relation Ff*N where N is the Normal force and Ff is the coefficient of friction. Now when the force of kinetic friction is equal to the force applied on the body, it will move at a constant speed as the net...

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The force of kinetic friction is given by the relation Ff*N where N is the Normal force and Ff is the coefficient of friction. Now when the force of kinetic friction is equal to the force applied on the body, it will move at a constant speed as the net force will be zero.

We are given that the coefficient of friction is 0.6. The block weighs 6 kg. So the normal force is equal to 6*9.8 = 58.8 N. The force of kinetic friction is equal to 58.8*0.6 = 35.28 N.

Therefore a force of 35.28N is being applied on the block in the horizontal direction to make it move at constant velocity of 5m/s.

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