What is the final temperature of this reaction ?
150.0 mL of 0.50 M HCl is added to 50.0 mL of 1.00 M NaOH to make 200.0 g of solution. Other data for this system include:
Initial Temp. of Solution - 42.3 degrees
Specific heat capacity of solution- 4.184J/g degrees C
Enthalpy change for neutralization -56 kj/mol
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Mass of solution (m) = 200g
Initial Temp. of Solution (T1) = 42.3 degrees C + 273 = 315.3 K
Specific heat capacity of solution (Cp) = 4.184 J/g degrees C
Enthalpy change for neutralization (Q) = 56 kj/mol = 56000 j/mol
Final Temp. of solution (T2) = ?
Q = m * Cp (T2 - T1)
56000 = 200 (T2 - 315.3)
56000 = 200T2 - 63060
56000 + 63060 = 200T2
119060 = 200 T2
T2 = 119060/200
T2 = 595.3 K
The final temperature of reaction is 595.3 K.
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