What is expression of linear function if its graph is passing through the points (-1,3) and (3,1)?
The equation of the line passing through the points (x1, y1) and (x2, y2) is given by ( y - y1) = [( y2 - y1)/(x2 - x1)]( x - x1)
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The standard form of a linear function f(x) is:
f(x) = ax + b
y = mx + n, where m represents the slope of the line and n represents the y intercept.
In this case, the graph of the function is passing through the given points.
By definition, a point belongs to a curve if the coordinates of the point verify the equation of the curve.
(-1,3) is on the line y = ax+b if and only if:
3 = a*(-1) + b
-a + b = 3 (1)
(3,1) belongs to the line y = ax+b if and only if:
1 = a*3 + b
3a + b = 1 (2)
We'll multiply (1) by 3:
-3a + 3b = 9 (3)
We'll add (3) to (2):
3a + b - 3a + 3b = 1 + 9
We'll eliminate like terms:
4b = 10
b = 5/2
From (1)=>a = b - 3
a = 5/2 - 3
a = -1/2
The function f(x) whose graph is passing through the given points is:
f(x) = -(1/2)*x + 5/2