What is the equation of the perpendicular bisector of the line between (6, 3) and (3, 4)?  

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The equation of the line between the points (6, 3) and (3, 4) is y – 3 = (x – 6)[(4 – 3)/(3 – 6)]

=> y – 3 = (x – 6)*( -1/3)

The slope of the line is (-1/3). The equation of the line perpendicular of this is 3. The midpoint of the given points is [( 6 + 3)/2 , (4 + 3)/2] = ( 9/2 , 7/2 )

The equation of the perpendicular bisector is y – 7/2 = 3( x – 9/2)

=> 2y – 7 = 6x – 27

=> 6x – 2y – 20 = 0

=> 3x – y – 10 = 0

The required equation of the perpendicular bisector is  3x – y – 10 = 0

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giorgiana1976 | College Teacher | (Level 3) Valedictorian

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Since the line is the bisectrix of the segment whose endpoints are (6, 3) and (3, 4), the midpoint of the segment is on this line.

We'll calculate the midpoint:

x mid = (6+3)/2

x mid = 9/2

y mid = (3+4)/2

y mid = 7/2

Since the bisectrix is perpendicular on the segment, the product of the slopes of the perpendicular lines is -1.

First, we'll write the equation of the segment:

(6-3)/(x-3) = (3-4)/(y-4)

3/(x-3) = -1/(y-4)

-x + 3 = 3y - 12

We'll put the equation in the slope intercept form:

3y = -x + 15

y = -x/3 + 5

The slope of the segment line is m1 = -1/3

m2*m1 = -1

m2 = -1/m1

m2 = 3

The equation of the perpendicular line is:

y - ymid = m2(x - xmid)

y - 7/2 = 3(x - 9/2)

(2y - 7)/2 = (6x - 27)/2

We'll simplify and we'll get:

2y - 7 = 6x - 27

The equation of the perpendicular bisectrix line is 6x - 2y - 20 = 0.

We'll simplify and we'll get:

3x - y - 10 = 0

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