What is the equation of the perpendicular bisector drawn between the points joining (4,2) and (4, 6) ?

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giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

Two lines are perpendicular if the product of their slopes is -1.

We'll write the equation of the line that passs through the points (4,2) and (4,6).

Let's note the points above as A and B.

We'll write the formula of the equation:

(xB-xA)/(x-xA) = (yB-yA)/(y-yA)

(4-4)/(x-4) = (6-2)/(y-2)

0/(x-4) = (4)/(y-2)

We'll cross multiply:

4(x-4) = 0

We'll divide by 4 both sides:

x-4 = 0

We'll add 4 both sides:

x = 4

We'll write the equation of the line in the standard form:

y = mx + n, where m is the slope and n is the y intercept.

 From the equation x = 4 it results that:

 y = 4

is the equation  of the line that is perpendicular to the line whose equation is x = 4.

william1941's profile pic

william1941 | College Teacher | (Level 3) Valedictorian

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The equation of the line between two points (x1, y1) and (x2, y2) is:

y - y1 = [( y2 -y1)/ (x2 -x1)] * (x - x1).

Here we have the points ( 4,2) and (4,6)

The line passing through them has a slope. (6 - 2) / (4 - 4) = inf

Or it is a vertical line.

The line perpendicular to a  vertical line is a horizontal line, with slope 0.

Also this line passes through the point lying between ( 4,2) and (4,6) which is (4 , 4 )

So the slope of the required line is 0 and the y- intercept is 4.

The line is  y= 0*x + 4.

So the equation of the required line is y=4.

neela's profile pic

neela | High School Teacher | (Level 3) Valedictorian

Posted on

To find the equation of the perpendicular bisector for line segment joining A(4,2) and B(4,6).

Solution:

The perpendicular bisector passes through the midpoint of the line segment joining  A and B . and is perpendicular to AB.

The mid point of the line AB is (Mx , My) = ( (Ax+Bx)/2 ,  (Ay+By)/2) ) = ( (4+4)/2 , (2+6)/2 ) = (4,4).

The slope of the line through the mid point M(4,4) shoulf be perpendicular to AB.

The slope of AB = (By-Ay)/(Bx-Ax) = (6-2)/(4-4) = infinite  or AB is parallel to y axis.

So the perpendicular to AB should be parallel to x axis ( or perpendicular to y axis). Ao the equation of this line is y = k.

Since y=k should pass thruogh  mid point of AB , that is M(4,4).

So y = 4 is the line which is the perpendicular bisector of A(4,2) and B(4,6)

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