# What is the equation of a parabola whose vertex (5,-2) and whose graph is 6 times taller than y=x^2? include y = as part of the answer

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Student Comments

aruv | Student

`x^2=y`

Vertex of the parabola is (0,0) and focus at (0,1/4).

A parabola taller than above parabola has vertex at (5,-2). Required parabola will open up.

Thus the required equation of the parabola will be:

`(x-5)^2=6(y+2)`

`y+2 = (x-5)^2/6`

`y = (x-5)^2/6 - 2`