What is the equation of the mirror image of the line 3x + 2y = 16 about the y-axis.
The equation of the line 3x + 2y = 16 can be rewritten as y = (-3/2)x + 8. This line has a slope of -3/2 and a y-intercept of 8.
The mirror image of the line about the y-axis is one with slope -(-3/2) = 3/2 and the same y-intercept.
This gives the equation of the line as: y = (3/2)*x + 8
=> 3x - 2y + 8 = 0
The graph of the original line 3x + 2y = 16 (in black ) and the mirror image 3x - 2y + 8 = 0 (in red) are given below:
The required equation of the mirror image is 3x - 2y + 8 = 0