What is the equation of the line perpendicular to y=2x-3 and that passes through (0;0)
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calendarEducator since 2008
write3,662 answers
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Given the point (0,0) passes through the line.
Then we will write the equation of the line:
(y-y1) = m(x-x1) where (x1,y1) is any point passes through the line, and m is the slope.
==> (y-0) = m( x-0)
==> y= mx.
Now we will find the slope (m).
We are given that the equation of the perpendicular line is y=2x-3.
Then we know that the slope of the perpendicular line is 2.
Also, we know that the product of the slopes of two perpendicular lines is -1.
==> 2*m = -1
==> m = -1/2,
Now we will substituteinto the equation.
==> y= (-1/2)x
=> y= -(1/2)x
==> 2y + x = 0
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calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
We have to find the equation of the line perpendicular to y=2x-3 and that passes through (0,0).
Now y = 2x - 3, has a slope 2
The slope of the line perpendicular to this is the neagtive inverse of -1/2.
Therefore the equation of the line passing through (0 , 0) and with the slope -1/2 is
y = (-1/2)*x
=> 2y = -x
=> x + 2y = 0
The required equation of the line perpendicular to y = 2x - 3 and that passes through (0, 0) is x + 2y = 0.
The slope intercept form of the equation of a line is y = mx + c where m is the slope and c is the y-intercept.
To determine the equation of a line perpendicular to y=2x-3 that passes through the point (0,0) first determine the slope of the given line.
It is in slope-intercept form and this gives the slope as 2. Now the product of the slope of two perpendicular lines is equal to -1.
If the slope of the required line is m, m*2 = -1, m = -1/2
The equation of a line with slope -1/2, and that passes through the point (0,0) is:
(y - 0)/(x - 0) = -1/2
y/x = -1/2
2y = -x
2y + x = 0
The line 2y + x = 0 is perpendicular to the line y=2x-3 and passes through (0,0)
Two lines are perpendicular when the product of their slopes is -1. Comparing the given equation to the point slope form of an equation of a line, we'll get the slope m1 = 2.
y = mx + n
y = 2x - 3
We also know that:
m1*m2 = -1, where m2 is the slope of the perpendicular line.
m2 = -1/m1
m2 = -1/2
The equation of the perpendicular line, that passes through the origin and has the slope m2 is:
y - 0 = m2(x - 0)
y = -x/2
y = -0.5x
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