# what is the equation for: find two consecutive odd integers whose sum is 116?

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Let the first odd integer be N.

Then, the next consecutive integer is (N+2).

Given that the sum of the integers is 116.

Then, we will write:

N + (N+2)= 116

Now we will simplify and solve the equation.

==> N+ N + 2 = 116

**==> 2N + 2 = 116**

Now we will solve for N.

Subtract 2 from both sides.

==> 2N = 116-2 = 114

==> 2N = 114

Now we will divide by 2.

==> N = 57

Then, the next consecutive integer is 57+2 = 59.

**Then, the integers are: 57 and 59**

Divide 116 by 2. That gives 2 even numbers i.e. 116= 58 +58, then subtract 1 from one of to get the lower integer and add 1 to get the higher i.e. 116= (58-1) + (58 +1). Then your answer is 116= 57 + 59