What is the empirical formula of a compound that contains:   1) 6.53gNa, 10.07g Cl

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enotechris | College Teacher | (Level 2) Senior Educator

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An Empirical Formula is one that gives the simplest whole-number ratio of atoms in a compound.  To determine that, we need to convert the mass to moles; this is done using the Atomic Mass Unit values found on the Periodic Table.  For sodium, its 22.99 amu; for chlorine, its 35.45 amu. The amu also tells us the molar mass, or the number of grams of each element to make a mole of that element, so for sodium it's 22.99 g/mol, for chlorine 35.45 g/mol. So to find out the number of moles for each element:

moles Na = (6.53 g) / (22.99 g/mol) = 0.28 moles

moles Cl = (10.07 g) / (35.45 g/mol) =  0.28 moles

Now to figure out the ratios of atoms in the compound, you would divide each mole value by the smallest calculated mole value; since the mole values are identical in this case, it comes out to 1:

(0.28 moles) / (0.28 moles) = 1

So there's 1 mole of Na for each mole of CL, and so we have NaCl.

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