What is the electron configuration of each substance below? Give the complete configuration and the noble gas shortcut configuration: a. Pd                            b. V+2

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To find the electron configuration, we need to first determine the number of electrons we have for the element. Palladium has 46 electrons so we know that our electron configuration must also have 46 electrons

Pd  1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d8

If we want to use the noble gas core configuration, we look back in the periodic table to the most recent noble gas before Pd which is Kr

[Kr] 5s2 4d8

For cations, we need to first find the electron configuration of the neutral element

V  1s2 2s2 2p6 3s2 3p6 4s2 3d3

Then we need to remove electrons from the highest n-value.  In the case of V^2+, we need to remove 2 electrons to have a positive charge and the electrons need to be removed from 4s orbital since that has the highest n-value.

V2+  1s2 2s2 2p6 3s2 3p6 3d3

As we did previously, we need to look for the previous noble gas which will be argon so our noble gas core configuration will be

[Ar] 3d3

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