The car was initially travelling at 80 km/h. It then accelerates at 12km/h^2 for 22 seconds.

22 seconds is equal to 22/3600 hours. Therefore the speed of the car after the period of acceleration is 80 + (22/3600)*12. The distance travelled during the period of acceleration is given by d = (u + v)*(t/2) where u is the initial velocity, v is the final velocity and t is the time during which the acceleration takes place.

Substituting the values provided in the question we get

d = [80 + 80 + (22/3600)*12]* (22/7200)

=> 0.489112 km

=> 489.11 m

**Therefore the required distance traveled is equal to 489.11 m**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now