What is the distance traveled by the car during the period of acceleration in the following case: A car that is travelling at 80 km/h, accelerates at 12km/h^2 for 22 seconds. Please give the answer as m to 2 decimal places.
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Tushar Chandra
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The car was initially travelling at 80 km/h. It then accelerates at 12km/h^2 for 22 seconds.
22 seconds is equal to 22/3600 hours. Therefore the speed of the car after the period of acceleration is 80 + (22/3600)*12. The distance travelled during the period of acceleration is given by d = (u + v)*(t/2) where u is the initial velocity, v is the final velocity and t is the time during which the acceleration takes place.
Substituting the values provided in the question we get
d = [80 + 80 + (22/3600)*12]* (22/7200)
=> 0.489112 km
=> 489.11 m
Therefore the required distance traveled is equal to 489.11 m
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