At what distance from a long straight wire carrying a current of 5.0 Amps is the magnitude of the magnetic field due to the wire equal to the strength of earth's magnetic field of about 5.0 x 10^-5 T ?
1 Answer | Add Yours
The magnetic field due to a current flowing through an infinitely long wire is given by `B = (mu*I)/(2*pi*r)` where B is the magnetic field, mu is the permeability of free space and equal to `4*pi*10^-7` T*m/A, and r is the radial distance.
The Earth's magnetic field is approximately `5*10^-5` T. If a wire carries a current of 5 A, the magnitude of the magnetic field due to the current is `5*10^-5` T at a distance r where:
`5*10^-5 = (4*pi*10^-7*5)/(2*pi*r)`
=> r = `(4*pi*10^-7*5)/(2*pi*5*10^-5)`
=> r = `(2*10^-2)`
The magnetic field around the wire is `5*10^-5` T at a distance `2*10^-2` m from the wire.
We’ve answered 318,915 questions. We can answer yours, too.Ask a question