What is the discriminant of quadratic equation x^2+11x+121=x+96?

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We have to find the discriminant of x^2+11x+121=x+96.

Now discriminant of ax^2 + bx + c = 0 is given by b^2 - 4ac.

x^2+11x+121=x+96

=> x^2 + 11x - x + 121 -96 = 0

=> x^2 + 10 x - 25

so a = 1 , b = 10 and c = 25

The discriminant is 10^2 - 4*1*25

= 100 - 100 = 0

Therefore the discriminant is 0.

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