What are the dimensions of the rectangle if the perimeter is 27 and the length is two times the width.

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justaguide's profile pic

justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

Let the length of the rectangle be L and let the width be W.

As the length is two times the width. L = 2W

The perimeter of the rectangle is the sum of the 4 sides and given by 2*(L + W)

=> 2*(W + 2W) = 27

=> 2*3*W = 27

=> W = 9/2

L = 2*W = 9

The length of the rectangle is 9 and the width is 9/2

hala718's profile pic

hala718 | High School Teacher | (Level 1) Educator Emeritus

Posted on

Let the length of the rectangle be L and the width be W.

Given that the perimeter is 27.

==> P = 2L + 2W = 27

We will divide by 2.

==> L + W = 27/2 ................(1)

Also, given that the length is two times the width.

==> L = 2*W .............(2)

We will substitute (2) into (1).

==> 2W + W = 27/2

==> 3W = 27/2

Now we will divide by 3:

==> w = 27/2*3 = 9/2 = 4.5

==> L = 2* 4.5 = 9

Then the dimensions of the rectangle are 9 and 4.5.

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