Given f(x)= 3sinx*cosx

We need to find the derivative.

We know that sin2x = 2sinx*cosx

==> sinx*cosx = sin2x /2

==> f(x)= (3/2) *sin2x.

Now we will differentiate.

==> f'(x)= (3/2)*(sin2x)'

==> f'(x)= (3/2)*2*cos2x

**==> f'(x)= 3cos2x **

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