Given f(x)= 3sinx*cosx
We need to find the derivative.
We know that sin2x = 2sinx*cosx
==> sinx*cosx = sin2x /2
==> f(x)= (3/2) *sin2x.
Now we will differentiate.
==> f'(x)= (3/2)*(sin2x)'
==> f'(x)= (3/2)*2*cos2x
==> f'(x)= 3cos2x
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