1 Answer | Add Yours
The definite integral `int_(0)^pi 3*tan x dx` has to be determined.
`int_(0)^pi 3*tan x dx`
=> `3*int_(0)^pi sin x/cos x dx`
let `cos x = y`
`dy = -sin x*dx`
=> `-3*int_(0)^pi (1/y) dy`
=> `-3*ln cos x` between 0 and pi
=> `-3*ln cos pi + 3*ln cos 0`
But `ln cos pi` is not defined as the logarithm of negative numbers is not defined.
The integral `int_(0)^pi 3*tan x dx` is not defined.
We’ve answered 319,190 questions. We can answer yours, too.Ask a question