The velocity `t` hours after the start is given by
`v = 25 + at`
where `a` is the required acceleration` `.
After 4 seconds `t=4/3600` (there are 3600 seconds in an hour) we have `v = 50`
`therefore`
`25 +4/3600a = 50`
`implies a = (25(3600))/4` mi/h^2
Now, 1 mile...
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The velocity `t` hours after the start is given by
`v = 25 + at`
where `a` is the required acceleration` `.
After 4 seconds `t=4/3600` (there are 3600 seconds in an hour) we have `v = 50`
`therefore`
`25 +4/3600a = 50`
`implies a = (25(3600))/4` mi/h^2
Now, 1 mile = 5280 feet so
` ``a = (25/4)(3600)(5280)` ft/h^2
`= 25/4(5280/3600)` ft/s^2 (3600^2 hours squared in a second squared)
Therefore a = 9.17 ft/s^2