`H_2O-----gtH^++OH^-`
`Cd(OH)_2-----gt Cd^(2+)+2OH^-`
` PH = -log[H^+]`
`8 =` `-log[H^+]`
`[H^+] = 10^-8 `
We know `K_w = [H^+][OH^-]`
Assume we have normal condtions;
So` K_w = 10^-8[OH^-] = 10^-14`
Therefore `[OH^-] = 10^-6`
`K_(sp) = [Cd^(2+)][OH^-]^2`
`[Cd^(2+)] = K_(sp)/[OH^-]^2`
=`2.5 xx 10^-14/[10^-6]^2`
= `2.5xx10^(-2)`
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