What is the common difference of an AP if the first term is 2 and the fifth term is 14 ?

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For an arithmetic progression, the nth term is given by: a + (n - 1)*d , where a is the first term and d is the common difference.

Here the first term is given as 2 and we have the fifth term as 14

So we have 14 = 2...

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For an arithmetic progression, the nth term is given by: a + (n - 1)*d , where a is the first term and d is the common difference.

Here the first term is given as 2 and we have the fifth term as 14

So we have 14 = 2 + (5 - 1)*d

=> 14 = 2 + 4d

=> 14 - 2 = 4d

=> 12 = 4d

=> d = 3

The required common difference is 3.

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