What is b if y= x^2 + 3x + b has two complex roots.?

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A quadratic equation ax^2 + bx + c = 0 has two complex roots if b^2 - 4ac < 0

In the given equation x^2 + 3x + b,

a = 1 , b = 3 and c = b( to be determined)

Now as b^2 - 4ac = 9 - 4b < 0

=> 4b > 9

=> b...

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