What is the average for 85 72 97 81 77 93 100 75 86 70 96 80

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shumbm's profile pic

Borys Shumyatskiy | College Teacher | (Level 3) Associate Educator

Posted on

Average is equal to (sum of all numbers)/(count of numbers).

Here count = 12, sum = (85 + 72 + 97 + 81 + 77 + 93 + 100 + 75 + 86 + 70 + 96 + 80) =
(157 + 178 + 170 + 175 + 156 + 176) =
(335 + 345 + 332) = 900 + 100 + 12 = 1012.

So the average is 1012/12 = 253/3 = 84 and 1/3 = 84,3333(3)... or approx. 84.33.

(please ask if you need mode or median or else)

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dkoprowski | eNotes Newbie

Posted on

First you want to add up all of the numbers. Your sum will be 1,012. Next, we need to divide the sum by the total number of numbers you added. Therefore it would be 1,012 / 12, which is 84.3. 

balajia's profile pic

balajia | College Teacher | (Level 1) eNoter

Posted on

Average= (sum of quantities)/(no of quantities)``

sum of quantities = 85+72+97+81+77+93+100+75+86+70+96+80

no of quantities=12

Average= (1012)/12 =84.33

kseddy123's profile picture

kseddy123 | College Teacher | (Level 1) Assistant Educator

Posted on

Let the given set be `i_(k) =` {85,72,97,81 ,77 ,93,100, 75, 86, 70, 96, 80}

Average of "n" numbers in a set  is calculated by = (sum of all n numbers)/ n

                                                                    = `(sum_(k=1)^n(i_(k)))/n`

Here n=12

sum of 12 numbers

= 85 + 72 + 97 + 81 + 77 + 93 + 100 + 75 + 86 + 70 + 96 + 80

= 1012

Now average is

Average of these 12 numbers = ` (sum_(k=1)^n(i_(k)))/n `

`=1012/12`

`= 84.3333 =84.34 `

``

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