The area enclosed by the line 3x + 2y = 8 and the x and y axes has to be determined.
The axes are perpendicular to each other. Rewrite the equation of the line 3x + 2y = 8 as `x/(8/3) + y/4 = 1` . The intercepts of the line are 8/3 and 4.
For the area formed by the three lines, the area is `(1/2)*b*h = (1/2)*4*(8/3) = 16/3`
The area enclosed by the line 3x + 2y = 8 and the x and y axes is `16/3` square units.