What is the area of the circle if the diagonal has endpoints ( 0, 3) and ( -2, 5)

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The diameter of the circle has end points ( 0,3) and ( -2, 5)

Now the diameter is sqrt [( 0+2)^2 + (3 - 5)^2]

=> sqrt [ 4 + 4]

=> 2 sqrt 2

The radius of the circle is 2 sqrt 2 / 2 = sqrt 2

The area give by pi* r^2 = pi * 2

Therefore the required area is 2* pi.

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We know that the area of the circle is presented by :

A = r^2 * pi where r is the radius.

Then we will need to calculate the length of the radius.

First we will determine center which is the midpoint.

==> Mx = ( 0-2)/2 = -1

==> My = ( 3 +5)/2 = 4

Then the center is the point ( -1,4)

Now we will calculate the radius length which is the length between the center ( -1, 4) and the endpoint (0, 3)

==> r = sqrt( -1-0)^2 + ( 4-3)^2

          = sqrt(1 + 1) = sqrt2

==> r = sqrt2

Now we will calculate the area.

==> A = r^2 * pi = sqrt2)^2 * pi = 2*pi = 2pi

==> The area of the circle is A = 2pi = 6.28 square units.

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