We have to find the anti-derivative of [ cos 2x - (cos x)^2]^-1
f(x) = [ cos 2x - (cos x)^2]^-1
=> f(x) = [(cos x)^2 - (sin x)^2 - (cos x)^2]^-1
=> f(x) = -(sin x)^-2
=> f(x) = -1 / (cosec x)^2
Int [ -1 / (cosec x)^2...
See This Answer Now
Start your subscription to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Already a member? Log in here.
We have to find the anti-derivative of [ cos 2x - (cos x)^2]^-1
f(x) = [ cos 2x - (cos x)^2]^-1
=> f(x) = [(cos x)^2 - (sin x)^2 - (cos x)^2]^-1
=> f(x) = -(sin x)^-2
=> f(x) = -1 / (cosec x)^2
Int [ -1 / (cosec x)^2 dx] = cot x + C
The required anti-derivative is cot x + C