What is the answer for question 9)? http://postimg.org/image/5gm0wsol3/

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embizze eNotes educator| Certified Educator

We are given that at time t=0 there is 16.32g of oxygen-19 and at time t=600sec there is .964g of oxygen-19. We are asked to find the half-life of oxygen-19:

Let n be the half-life. Then `16.32(1/2)^(600/n)=.964`

** Note that at time n the formula gives 1/2 of 16.32 as required.**




`600/n ln(1/2)=ln(.962/16.32)`





The half-life is approximately 147 seconds.

The graph:

(The red line is when there is 8.16g of oxygen-19; about 147 seconds)