# What is the answer for question 3. a) ? http://postimg.org/image/scirn1jtt/

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Student Comments

pramodpandey | Student

We will use

`logx^m=m logx`

`log(xy)=logx+logy`

`log(x/y)=logx-logy`

We have

`log_2((x^2-9)/x^3)^3`

`=3log_2((x^2-9)/x^3)`

`=3{log_2(x^2-9)-log_2(x^3)}`

`=3log_2(x^2-9)-3xx3log_2(x)`

`=3log_2(x^2-9)-9log_2(x)`