1 Answer | Add Yours
Let board making angle `theta` with the horizontal .In t=2 seconds rolled over a distance S = 1.3 m.
We ignore the size of the ball, which can slow down the ball.
Let g=acceleration due to gravity = 9.8 m/s²
a=acceleration down the board
t = 2 sec
`s=ut+(1/2) g t^2 sin(theta)` (i)
differentiate (i) with respect to t
`(ds)/(dt)=u+g t sin(theta)`
But `(ds)/(dt)=speed =v` (say)
`v=g t(.0663)` , put value of g
v alog y -axis and t along x-axis.
We’ve answered 319,865 questions. We can answer yours, too.Ask a question