The equation given is in the form V = a * b^y

where a = original value of the car, b = rate of depreciation, and

y number of years.

So, for the first question rate of depreciation is 0.85 or 85%.

For the second question, we replace the y by 5.

`V = 25000(0.85)^5 = 25000*0.4437053125 = $11092.63 `

` `Therefore, **the value of the car after 5 years is $11.092.63**.

For the last question, we will take the 10% of the original value.

`0.10 * 25000 = $2500`

So, our V = $2500, and we will solve for y.

`2500 = 25000(0.85)^y`

Divide both sides by 25000.

`0.10 = 0.85^y`

Take the natural logarithm of both sides.

`ln0.10 = ln0.85^y`

Use the property: lnu^v = vlnu on right side.

`ln0.10 = yln0.85`

Divide both sides by ln0.85.

`y = ln0.10/ln0.85 = 14.17 ` years or 14 years and 2 months.