If y=8^(cos x), what is dy/dx?

Expert Answers

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We have y = 8^cos x.

We use the chain rule to find the derivative of 8^(cos x)

Now the derivative of a^x is a^x log a and the derivative of cos x is -sin x.

y' = log 8 * 8^cos x * (cos x)'

=> y' = -log 8 * 8^cos x* sin x

Therefore dy/dx = -log 8 * 8^cos x* sin x

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