What angle does this vector (1,6,-5) make with the XY plane?
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thilina-g
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The equation of xy plane is `n = (0,0,1).`
The line is `b = (1,6,-5)`
The angle between the line and xy plane is A
`n.b = |n||b| sinA`
`(0,0,1).(1,6,-5) = |(0,0,1)|xx |(1,6,-5)| xx sinA`
`-5 = 1 xx sqrt(62) xx sinA`
`sinA = (-5)/sqrt(62)`
`sinA = -0.6350`
`A = -39.42` degrees.
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