What amount of energy is required to completely ionize 26.8 grams of carbon atoms in the gas phase (C(g)) if the ionization energy of C(g) is 1086 kJ/mole? Answer in units of J
The ionization energy of carbon is 1086 kJ/mole. The molar mass of carbon is 12 g/mole. 26.8 grams of carbon is equivalent to 26.8/12 = 67/30 moles.
The energy required to ionize 67/30 moles of carbon is equal to (67/30)*1086 = 2425.4 kJ = 2425.4*10^3 J
The amount of energy required to completely ionize 26.8 gram of carbon in the gas phase is equal to 2425.4*10^3 J