Let the age of Sheila be S, Nicole's age be N and Steve's age be T.

Sheila's age is 2 more than Nicole's age.

S = 2 + 2*N

The sum of Sheila and Nicole's age is the same as that of Steve

T = S + N

Steve's age is 10 less than 5 times the age of Nicole

T = 5*N - 10

Using the three equations we have derived, we can find S, T and N

Substituting S = 2 + 2*N in T = S + N

=> T = 2 + 2N + N = 2 + 3N

Substituting this in T = 5*N - 10

=> 2 + 3N = 5N - 10

=> 2N = 12

=> N = 12 / 2 = 6

T = 2 + 3N = 2 + 18 = 20

S = 2 + 2N = 2 + 12 = 14

**The age of Sheila is 14 , Nicole is 6 years old and Steve is 20 years old.**