# What are the ages of Sheila, Steve and Nicole? Sheila's age is two years more than twice Nicole's age. The sum of their ages is the same as Steve's age. If Steve's age is 10 years less than five times Nicole's age, find the age of each person. Let the age of Sheila be S, Nicole's age be N and Steve's age be T.

Sheila's age is 2 more than Nicole's age.

S = 2 + 2*N

The sum of Sheila and Nicole's age is the same as that of Steve

T = S + N

Steve's age...

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Let the age of Sheila be S, Nicole's age be N and Steve's age be T.

Sheila's age is 2 more than Nicole's age.

S = 2 + 2*N

The sum of Sheila and Nicole's age is the same as that of Steve

T = S + N

Steve's age is 10 less than 5 times the age of Nicole

T = 5*N - 10

Using the three equations we have derived, we can find S, T and N

Substituting S = 2 + 2*N in T = S + N

=> T = 2 + 2N + N = 2 + 3N

Substituting this in T = 5*N - 10

=> 2 + 3N = 5N - 10

=> 2N = 12

=> N = 12 / 2 = 6

T = 2 + 3N = 2 + 18 = 20

S = 2 + 2N = 2 + 12 = 14

The age of Sheila is 14 , Nicole is 6 years old and Steve is 20 years old.

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