If acceleration is given by a, u is the initial velocity, v is the final velocity, t is the time taken and s is the distance traveled, we have:

v = u + at

s = ut + (1/2)at^2

Here, Maggie and Judy cross the finish line of a 100 m race in 12 s.

Maggie attained the maximum speed in 2 seconds which was maintained for the rest of the time.

Let the acceleration be Am, Vmax = Am*2, S = (1/2)*Am*4 = 2*Am

For the rest of the distance 100 - S = 2*Am*10

100 - 2*Am = 20Am

=> 100 = 22Am

=> Am = 100/22 m/s^2

Vmax = 100/11 m/s

Maggie's acceleration was 100/22 m/s^2 and her maximum velocity was 100/11 m/s

For Judy, Vmax = 2.6*Aj, S = (1/2)*Aj*(2.6)^2 = 3.38*Aj

100 - 3.38Aj = 2.6*Aj*9.4

=> 100 = 27.82*Aj

Aj = 100/27.82 m/s^2

Vmax = 260/27.82 m/s

Judy's acceleration was 100/27.82 m/s^2 and her maximum velocity was 260/27.82 m/s

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