# What is the acceleration required to avoid a collision in the following case?A high speed passenger train traveling at 100 mi/hr rounds a bend, the engineer is shocked to see that a locomotive has...

What is the acceleration required to avoid a collision in the following case?

A high speed passenger train traveling at 100 mi/hr rounds a bend, the engineer is shocked to see that a locomotive has improperly entered onto the track from a siding 0.28 mi ahead. The locomotive is moving at 18 mi/hr in the same direction as the passenger train. The engineer of the passenger train immediately applies the breaks. What must the magnitude of the resulting constant acceleration if a collision is to be just avoided?

*print*Print*list*Cite

### 1 Answer

The passenger train is traveling at 100 mi/hr when the driver makes the turn. The locomotive train is on the same tracks as the passenger train and moving towards it at 18 mi/hr. The distance between the two trains is 0.28 mi.

Adding the velocities of the two trains, the net velocity with which the passenger train is approaching the locomotive is 118 mi/hr. The distance between them is 0.28 mi within which the passenger train has to stop to avoid a collision.

Let the acceleration required be A.

Using the formula v^2 - u^2 = 2*a*s

=> 0 - 118^2 = 2*A*0.28

=> A = -118^2/2*0.28

=> A = -24864.2 mi/hr^2

The deceleration due to the brakes should be 24864.2 mi/hr^2 to avoid a collision.