What is the absolute value of the number (1+i)(1+2i)(1+3i)?

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First find the product of (1 + i)(1 + 2i)(1 + 3i)

z = (1 + 3i - 2)(1 + 3i)

=> z = (-1 + 3i)(1 + 3i)

=> z = 9i^2 - 1

=> z = -9 - 1

=> z = -10

The absolute value of -10 is 10

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