First find the product of (1 + i)(1 + 2i)(1 + 3i)

z = (1 + 3i - 2)(1 + 3i)

=> z = (-1 + 3i)(1 + 3i)

=> z = 9i^2 - 1

=> z = -9 - 1

=> z = -10

**The absolute value of -10 is 10**

First find the product of (1 + i)(1 + 2i)(1 + 3i)

z = (1 + 3i - 2)(1 + 3i)

=> z = (-1 + 3i)(1 + 3i)

=> z = 9i^2 - 1

=> z = -9 - 1

=> z = -10

**The absolute value of -10 is 10**