# A Web music store offers two versions of a popular song. The size of the standard version is  2.6  megabytes (MB). The size of the high-quality version is  4.3 MB. Yesterday, the...

A Web music store offers two versions of a popular song. The size of the standard version is

2.6

megabytes (MB). The size of the high-quality version is

4.3

MB. Yesterday, the high-quality version was downloaded four times as often as the standard version. The total size downloaded for the two versions was

5346

ishpiro | Certified Educator

Let's denote the number of downloads of the standard version by x and the number of downloads of the high-quality version by y.

y = 4x.

2.6x + 4.3y = 5346.

These two equations can be solved together as a system. The expression for y in terms of x, y = 4x, can be substituted into the second equation:

2.6x + 4.3(4x) = 5346.

2.6x + 17.2x = 5346

19.8x = 5346

Divide both sides by 19.8 to get 5346:

`x = 5346/19.8 =270 `

hkj1385 | Certified Educator

Thus, total size of high quality version = 5346 - 2.6x

Now, as per the question, the high quality version downloaded = 4*x

Thus, 4x*4.3 = 5346-2.6x

or, 17.2x = 5346-2.6x

or, 19.8x = 5346