Are these two expressions equal? `(x^2+4x-1)/(x+1)` `=` `(x+3)` `-` `4/(x+1)` Grateful for an answer..
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Yes, these two expressions are equal.
`(x^2 +4x-1)/(x+1)= (x+3) - (4/(x+1))`
Multiply each term so that all terms have a denominator of (x+1).
`(x^2+4x-1)/(x+1) =(x^2+x)/(x+1) + (3x+3)/(x+1) - (4)/(x+1)`
The numerators of expressions with equal denominators can be combined.
`(x^2+4x-1)/(x+1)=(x^2+x+3x+3-4)/(x+1)`
Combine similar terms in the polynomial.
`(x^2+4x-1)/(x+1)=(x^2+4x-1)/(x+1)`
Multiply each term in the equation by (x+1) to get rid of the denominators.
`(x^2+4x-1)/(x+1)* (x+1) =(x^2+4x-1)/(x+1)*(x+1)`
Simplify.
`x^2+4x-1=x^2+4x-1`
`x^2+4x-1-x^2-4x =-1`
Since `x^2` and `-x^2` cancel each other out and `+4x` and `-4x` also cancel, we are left with
`-1=-1`
Since `-1=-1` , the expressions are equal.
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