The vertices of triangle ABC are A(1,2), B(7,3), C(5,7). Find the midpoint of side BC.
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The mid point of a line joining the points (x1, y1) and ( x2, y2) is given by [(x1 + x2) / 2 , (y1 + y2)/2]
For the side, BC the coordinates of B are (7 , 3) and those of C are ( 5, 7).
The mid point of BC is [(7+5)/2 , (3+7)/2]
=> (12/2 , 10/2)
=> (6, 5)
The required mid-point is ( 6, 5)
Related Questions
We'll recall the formula of the midpoint of a segment and we'l apply it to determine the coordinates of the midpoint M of the side BC.
xM = (xB + xC)/2
yM = (yB + yC)/2
We'll substitute the coordinates of B and C in the relations above:
xM = (7 + 5)/2
xM = 6
yM = (3 + 7)/2
yM = 5
The midpoint M of BC is: M(6 ; 5).
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