The vertices of triangle ABC are A(1,2), B(7,3), C(5,7). Find the midpoint of side BC.

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The mid point of a line joining the points (x1, y1) and ( x2, y2) is given by [(x1 + x2) / 2 , (y1 + y2)/2]

For the side, BC the coordinates of B are (7 , 3) and those of C are ( 5, 7).

The mid point of BC is [(7+5)/2 , (3+7)/2]

=> (12/2 , 10/2)

=> (6, 5)

The required mid-point is ( 6, 5)

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giorgiana1976 | Student

We'll recall the formula of the midpoint of a segment and we'l apply it to determine the coordinates of the midpoint M of the side BC.

xM = (xB + xC)/2

yM = (yB + yC)/2

We'll substitute the coordinates of B and C in the relations above:

xM = (7 + 5)/2

xM = 6

yM = (3 + 7)/2

yM = 5

The midpoint M of BC is: M(6 ; 5).

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