Vertex of the function . Determine the vertex of the function f(x)=3x^2-12x
- print Print
- list Cite
Expert Answers
calendarEducator since 2010
write12,544 answers
starTop subjects are Math, Science, and Business
For a parabola y = ax^2 + bx + c, the vertex is given by the coordinates: (-b/2a , -(b^2...
(The entire section contains 52 words.)
Unlock This Answer Now
Start your 48-hour free trial to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Related Questions
- How to find domain of function f(x)=(x-2)/(x^2-4)?How to find domain of function f(x)=(x-2)/(x^2-4)?
- 1 Educator Answer
- Determine the inverse function of f(x)=2x/2(x^3+x) .
- 1 Educator Answer
- Given y=3x/(x^2-9) determine the numbers m and n if y=m/(x-3)+n/(x+3)
- 1 Educator Answer
- How to determine the vertex of parabola .Write the vertex of the parabola y=x^2+4x .
- 1 Educator Answer
- Find the inverse of f(x)=5tan(3x+4)
- 2 Educator Answers
We know that the coordinates of a vertex of a parabola are:
V(-b/2a ; -delta/4a)
a,b,c are the coefficients of the quadratic:
y = ax^2 + bx + c
Comparing, we'll identify the coefficients:
a = 3, b = -12 , c = 0
We'll calculate the x coordinate of the vertex:
xV = -(-12)/2*3
xV = 12/6
xV = 2
We'll calculate the y coordinate of the vertex:
yV = -delta/4a
delta = b^2 - 4ac
delta = 144 - 4*3*0
delta = 144
yV = -144/4*3
yV = -144/12
yV = -12
The requested coordinates of the vertex of the parabola are: V(2 , -12).
Student Answers