Vertex of the function . Determine the vertex of the function f(x)=3x^2-12x

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For a parabola y = ax^2 + bx + c, the vertex is given by the coordinates: (-b/2a , -(b^2 - 4ac)/4a)

The equation of the parabola given is : y = 3x^2-12x

substituting the values, the vertex is

(12/6 , -(144 - 0)/12)

=> (2 , -12)

The vertex of y = 3x^2-12x lies at (2 , -12)

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