Vertex of the function .Determine the vertex of the function f(x)=3x^2-12x
2 Answers
justaguide | College Teacher | (Level 2) Distinguished Educator
For a parabola y = ax^2 + bx + c, the vertex is given by the coordinates: (-b/2a , -(b^2 - 4ac)/4a)
The equation of the parabola given is : y = 3x^2-12x
substituting the values, the vertex is
(12/6 , -(144 - 0)/12)
=> (2 , -12)
The vertex of y = 3x^2-12x lies at (2 , -12)
giorgiana1976 | College Teacher | (Level 3) Valedictorian
We know that the coordinates of a vertex of a parabola are:
V(-b/2a ; -delta/4a)
a,b,c are the coefficients of the quadratic:
y = ax^2 + bx + c
Comparing, we'll identify the coefficients:
a = 3, b = -12 , c = 0
We'll calculate the x coordinate of the vertex:
xV = -(-12)/2*3
xV = 12/6
xV = 2
We'll calculate the y coordinate of the vertex:
yV = -delta/4a
delta = b^2 - 4ac
delta = 144 - 4*3*0
delta = 144
yV = -144/4*3
yV = -144/12
yV = -12
The requested coordinates of the vertex of the parabola are: V(2 , -12).