For a parabola y = ax^2 + bx + c, the vertex is given by the coordinates: (-b/2a , -(b^2 - 4ac)/4a)

The equation of the parabola given is : y=x^2+4x

substituting the values, the vertex is

(-2/2 , -(16 - 0)/4)

=> (-1 , -4)

**The vertex of y=x^2+4x lies at (-1 , -4)**

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