Verify that `y = -tcos(t) - t` is a solution of the initial value problem `t(dy/dt) = y + t^2sin(t)` ` ` `y(pi) = 0`
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Lee Lubowitz
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First we need to find derivative
`dy/dt=-cos t+tsin t-1`
Here we've used product rule to differentiate `-tcos t.`
Now we insert `dy/dt` and `y` into the initial value problem.
`t(-cos t+tsin t-1)=-tcos...
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