The trigonometric relation `tan^2x-sin^2x=tan^2x*sin^2x` has to be verified.
Start from the left hand side
`tan^2x-sin^2x `
= `sin^2x(1/(cos^2x) - 1)`
= `sin^2x*((1 - cos^2x)/(cos^2x))`
= `((sin^2x)/(cos^2x))*sin^2x`
= `tan^2x*sin^2x`
This proves that `tan^2x-sin^2x=tan^2x*sin^2x`
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