Verify if the function is odd or even? y=17x^3-12x^2

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A function is odd if f(-x) = -f(x) and even if f(-x) = f(x)

Here we have f(x) = y= 17x^3 - 12x^2

f(-x) = -17x^3 - 12x^2

f(x) = 17x^3 - 12x^2

-f(x) = -17x^3 + 12x^2

So we see that f(-x) = -17x^3 - 12x^2 is neither equal...

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A function is odd if f(-x) = -f(x) and even if f(-x) = f(x)

Here we have f(x) = y= 17x^3 - 12x^2

f(-x) = -17x^3 - 12x^2

f(x) = 17x^3 - 12x^2

-f(x) = -17x^3 + 12x^2

So we see that f(-x) = -17x^3 - 12x^2 is neither equal to f(x) nor equal to -f(x).

Therefore the function is neither even nor odd.

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